Probability
This page pairs well with Statistics.
Elements of Probability Theory
A random experiment has uncertain outcomes. The sample space \(S\) is the set of all possible outcomes. An event \(E\) is a subset of \(S\). The certain event is \(S\); the impossible event is \(\varnothing\).
A probability space \((S,\mathcal{F},P)\) consists of a sample space \(S\), a \(\sigma\)-algebra \(\mathcal{F}\subseteq 2^S\), and a function \(P:\mathcal{F}\to[0,1]\) such that:
- \(P(\varnothing)=0\), \(P(S)=1\);
- \(P(E)\ge 0\) for all \(E\in\mathcal{F}\);
- (\(\sigma\)-additivity) For any countable family of pairwise disjoint events \(\{E_i\}\), \(P\!\left(\bigcup_i E_i\right)=\sum_i P(E_i)\).
For any events \(E_1,E_2\), \[ P(E_1\cup E_2)=P(E_1)+P(E_2)-P(E_1\cap E_2). \] More generally, \[ P\!\left(\bigcup_{i=1}^n E_i\right)=\sum_i P(E_i)-\sum_{i<j}P(E_i\cap E_j)+\cdots+(-1)^{n-1}P\!\left(\bigcap_{i=1}^n E_i\right). \]
If \(P(F)>0\), define \[ P(E\mid F)=\frac{P(E\cap F)}{P(F)}. \] Equivalently, \(P(E\cap F)=P(E\mid F)P(F)\).
For any events \(E_1,\dots,E_n\) with \(P(E_1\cap\cdots\cap E_{k-1})>0\) for each \(k\), \[ P\!\left(\bigcap_{k=1}^n E_k\right)=\prod_{k=1}^n P\!\left(E_k\mid \bigcap_{j<k}E_j\right). \]
If \(\{B_i\}_{i\in I}\) is a (finite or countable) partition of \(S\) with \(P(B_i)>0\), then for any event \(A\), \[ P(A)=\sum_{i\in I} P(A\mid B_i)P(B_i). \]
Given a partition \(\{B_i\}\) with \(P(B_i)>0\) and any event \(A\) with \(P(A)>0\), \[ P(B_i\mid A)=\frac{P(A\mid B_i)P(B_i)}{\sum_j P(A\mid B_j)P(B_j)}. \]
Events \(E\) and \(F\) are independent if \(P(E\cap F)=P(E)P(F)\) (equivalently, if \(P(F)>0\), then \(P(E\mid F)=P(E)\)). A family \(\{E_i\}\) is pairwise independent if each pair is independent; it is mutually independent if \[ P\!\left(\bigcap_{i\in J} E_i\right)=\prod_{i\in J}P(E_i)\quad\text{for every finite }J. \]
If \(X\ge 0\) and \(a>0\), then \[ \mathbb P(X\ge a)\le \frac{\mathbb E[X]}{a}. \]
If \(\mathbb E[X]=\mu\) and \(\operatorname{Var}(X)=\sigma^2<\infty\), then for any \(k>0\), \[ \mathbb P\!\big(|X-\mu|>k\sigma\big)\le \frac{1}{k^2}. \]
If \(h\) is convex and \(X\) is integrable, then \[ h\!\big(\mathbb E[X]\big)\le \mathbb E\!\big[h(X)\big]. \] (Equality iff \(h\) is affine on the support of \(X\) or \(X\) is degenerate.)
Random Variables
A (real-valued) random variable is a measurable function \(X:S\to\mathbb{R}\). We distinguish \(X\) (the variable), a realised value \(x=\text{generic number}\), and the observed \(\,\hat{x}=X(\hat{\omega})\).
The CDF of \(X\) is \[ F_X(x)=P(X\le x),\quad x\in\mathbb{R}. \] Key properties:
- non-decreasing;
- right-continuous;
- \(\lim_{x\to-\infty}F_X(x)=0\);
- \(\lim_{x\to+\infty}F_X(x)=1\).
\(F_X\) completely characterises the distribution.
\(X\) is discrete if \(F_X\) is a step function with (at most) countably many jumps at \(\{x_k\}\). The probability mass function (pmf) is \(p_X(x)=P(X=x)\), with \(\sum_{k}p_X(x_k)=1\) and \[ F_X(x)=\sum_{x_k\le x} p_X(x_k),\qquad p_X(x_k)=F_X(x_k)-F_X(x_k^-). \]
\(X\) is continuous if \(F_X\) is continuous (hence \(P(X=x)=0\) for all \(x\)). A probability density function (pdf) \(f_X\) satisfies \[ P(X\in A)=\int_A f_X(x)\,dx,\qquad F_X(x)=\int_{-\infty}^x f_X(y)\,dy,\quad\text{and}\quad f_X(x)=\frac{d}{dx}F_X(x) \] (where differentiable), with \(f_X\ge 0\) and \(\int_\mathbb{R} f_X=1\).
For a r.v. \(X\) with CDF \(F_X\), \[\mathbb{E}[X]=\int_{-\infty}^{\infty} x\,dF_X(x) =\begin{cases}\displaystyle \sum_{x\in S_X} x\,p_X(x), & \text{(discrete)}\\ \displaystyle \int_{S_X} x\,f_X(x)\,dx, & \text{(continuous).}\end{cases}\]
Linearity: \(\mathbb{E}[aX+b]=a\,\mathbb{E}[X]+b\).
Existence: \(\mathbb{E}[X]\) is finite iff \(\mathbb{E}[|X|]<\infty\).
The $k$-th (raw) moment: \(\mathbb{E}[X^k]\). The $k$-th central moment: \(\mathbb{E}[(X-\mu)^k]\) with \(\mu=\mathbb{E}[X]\). The variance is the 2nd central moment: \[ \operatorname{Var}(X)=\mathbb{E}\!\left[(X-\mu)^2\right]\ge 0,\quad \sigma=\sqrt{\operatorname{Var}(X)}. \] Useful identities: \[ \operatorname{Var}(X)=\mathbb{E}[X^2]-(\mathbb{E}[X])^2,\qquad \operatorname{Var}(aX+b)=a^2\,\operatorname{Var}(X). \]
For a r.v.\ \(X\), the moment generating function is \(M_X(u)=\mathbb E[e^{uX}]\) (where finite near \(u=0\)). If it exists, then \(M_X^{(n)}(0)=\mathbb E[X^n]\). Key facts: (i) Uniqueness — \(M_X=M_Y\) implies \(X\overset{d}=Y\); (ii) Independence — for independent \(X,Y\), \[ M_{X+Y}(u)=M_X(u)\,M_Y(u). \]
For continuous \(X\), the \(100k\%\) quantile is \(Q_X(k)=F_X^{-1}(k)\), \(0<k<1\).
A QQ-plot compares sample order statistics \(\{x_{(k)}\}\) to theoretical quantiles \(\{F^{-1}(p_k)\}\) (e.g.\ \(p_k=(k-0.5)/n\)); points should lie roughly on a straight line if the model fits.
If \(X_1,X_2,\dots\) are i.i.d.\ with \(\mathbb E[X_i]=\mu\) and \(\operatorname{Var}(X_i)=\sigma^2<\infty\), then for every \(\varepsilon>0\), \[ \lim_{n\to\infty}\mathbb P\!\left(\big|\,\overline X_n-\mu\,\big|\ge \varepsilon\right)=0, \] i.e.\ \(\overline X_n \xrightarrow{\ \mathbb P\ } \mu\).
Under the same conditions, \[ \mathbb P\!\left(\lim_{n\to\infty}\overline X_n=\mu\right)=1, \] i.e.\ \(\overline X_n \xrightarrow{\ \mathrm{a.s.}\ } \mu\).
If \(X_1,\dots,X_n\) are i.i.d.\ with mean \(\mu\) and variance \(0<\sigma^2<\infty\), then \[Z_n=\sqrt{n}\,\frac{\overline X_n-\mu}{\sigma}\ \xRightarrow[n\to\infty]{d}\ N(0,1),\] equivalently \(\ \mathbb P(Z_n\le z)\to \Phi(z)\ \) for all \(z\in\mathbb R\).
\(X_n \xrightarrow{\text{a.s.}} X \;\Rightarrow\; X_n \xrightarrow{P} X \;\Rightarrow\; X_n \xrightarrow{d} X.\) Definitions:
- In distribution: \(F_{X_n}(x)\to F_X(x)\) at continuity points of \(F_X\).
- In probability: \(\forall\varepsilon>0,\ \mathbb P(|X_n-X|>\varepsilon)\to0.\)
- Almost surely: \(\mathbb P(\lim_{n\to\infty}X_n=X)=1.\)
If \(X\sim\mathrm{Bin}(n,p)\), then \(\dfrac{X-np}{\sqrt{np(1-p)}}\Rightarrow N(0,1)\) as \(n\to\infty\).
Random Vectors
A random vector \((X_1,\dots,X_n):S\to\mathbb{R}^n\) has joint distribution. For \((X_1,X_2)\), the joint CDF is \[ F_{X_1X_2}(x_1,x_2)=P(X_1\le x_1,\,X_2\le x_2), \] with: non-decreasing in each coordinate, right-continuous, and limits \(F_{X_1X_2}(+\infty,+\infty)=1\), \(F_{X_1X_2}(x_1,-\infty)=F_{X_1X_2}(-\infty,x_2)=0\).
Marginals: \(F_{X_1}(x_1)=\lim_{x_2\to +\infty}F_{X_1X_2}(x_1,x_2)\) (and symmetrically for \(X_2\)).
Independence: \(X_1\) and \(X_2\) are independent iff \(F_{X_1X_2}(x_1,x_2)=F_{X_1}(x_1)F_{X_2}(x_2)\) for all \((x_1,x_2)\) (equivalently, \(p_{X_1X_2}=p_{X_1}p_{X_2}\) in discrete case; \(f_{X_1X_2}=f_{X_1}f_{X_2}\) in continuous case).
For \(g:\mathbb{R}^2\to\mathbb{R}\), \[\mathbb{E}[g(X_1,X_2)]= \begin{cases}\displaystyle \sum_{x_1,x_2} g(x_1,x_2)\,p_{X_1X_2}(x_1,x_2), & \text{(discrete)}\\ \displaystyle \iint g(x_1,x_2)\,f_{X_1X_2}(x_1,x_2)\,dx_2\,dx_1, & \text{(continuous).}\end{cases}\]
In particular, \(\mathbb{E}[aX_1+bX_2]=a\,\mathbb{E}[X_1]+b\,\mathbb{E}[X_2]\).
Let \(\mu_k=\mathbb{E}[X_k]\). The covariance is \[ \operatorname{Cov}(X_1,X_2)=\mathbb{E}[(X_1-\mu_1)(X_2-\mu_2)], \] and the correlation coefficient is \[ \rho(X_1,X_2)=\frac{\operatorname{Cov}(X_1,X_2)}{\sqrt{\operatorname{Var}(X_1)\operatorname{Var}(X_2)}}\in[-1,1]. \] If \(X_1\perp X_2\), then \(\operatorname{Cov}(X_1,X_2)=0\), and \[ \operatorname{Var}(X_1+X_2)=\operatorname{Var}(X_1)+\operatorname{Var}(X_2). \]
For \(X=(X_1,\dots,X_n)^\top\), define the mean vector \[ \mu_X=\mathbb{E}[X]=\big(\mathbb{E}[X_1],\dots,\mathbb{E}[X_n]\big)^\top, \] and the covariance matrix \(\Sigma_X=\operatorname{Cov}(X)\) with \((i,j)\) entry \(\operatorname{Cov}(X_i,X_j)\). If \(Y=AX+b\) with constant matrix \(A\) and vector \(b\), then \[ \mathbb{E}[Y]=A\,\mu_X+b,\qquad \operatorname{Cov}(Y)=A\,\Sigma_X\,A^\top. \]
For continuous \((X,Y)\) with joint pdf \(f_{X,Y}\) and marginal \(f_Y(y)>0\), \[ f_{X\mid Y}(x\mid y)=\frac{f_{X,Y}(x,y)}{f_Y(y)}. \] Then \[ \mathbb E[g(X)\mid Y=y]=\int g(x)\,f_{X\mid Y}(x\mid y)\,dx. \] (Discrete analogues use pmfs and sums.)
\((X_1,X_2)\) is Gaussian with mean \(\mu=(\mu_1,\mu_2)\) and covariance \(V\) if \[ f(x)=\frac{1}{2\pi \sqrt{\det V}} \exp\!\Big(-\tfrac12\,(x-\mu)^\top V^{-1}(x-\mu)\Big). \]
Common Distributions
If \(X\sim U[\alpha,\beta]\) with \(\alpha<\beta\), then \[ f_X(x)=\frac{1}{\beta-\alpha}\;1_{\{\alpha\le x\le\beta\}},\qquad F_X(x)=\frac{x-\alpha}{\beta-\alpha}\ (x\in[\alpha,\beta]), \] \[ \mathbb E[X]=\frac{\alpha+\beta}{2},\quad \mathrm{Var}(X)=\frac{(\beta-\alpha)^2}{12}. \] For any \(a<b\subseteq[\alpha,\beta]\): \(\mathbb P(a<X<b)=\frac{b-a}{\beta-\alpha}\).
\[f_U(u)=1_{[0,1]}(u),\quad F_U(u)=\begin{cases}0,&u<0\\u,&0\le u\le 1\\1,&u>1\end{cases}\] \(\mathbb E[U]=\tfrac12,\ \mathrm{Var}(U)=\tfrac1{12}\).
A Bernoulli r.v. \(X\sim \mathrm{Bern}(\pi)\) takes values in \(\{0,1\}\) with \(\mathbb P(X=1)=\pi,\ \mathbb P(X=0)=1-\pi\).
Moments: \(\mathbb E[X]=\pi,\ \mathrm{Var}(X)=\pi(1-\pi)\).
mgf: \(\varphi_X(s)=(1-\pi)+\pi e^{s}\).
If \(X=\sum_{i=1}^n X_i\) with \(X_i\overset{\text{i.i.d.}}{\sim}\mathrm{Bern}(\pi)\), then \[ X\sim \mathrm{Bin}(n,\pi),\quad \mathbb P(X=x)=\binom{n}{x}\pi^x(1-\pi)^{n-x},\ x=0,\dots,n. \] \(\mathbb E[X]=n\pi,\quad \mathrm{Var}(X)=n\pi(1-\pi),\quad \varphi_X(s)=[(1-\pi)+\pi e^s]^{n}\). (Reproductive property: \(X_1\sim\mathrm{Bin}(n_1,\pi)\), \(X_2\sim\mathrm{Bin}(n_2,\pi)\) independent \(\Rightarrow\ X_1+X_2\sim\mathrm{Bin}(n_1+n_2,\pi)\).)
Given i.i.d. Bernoulli trials with success prob. \(\pi\), let \(X=\min\{i\in\mathbb N: X_i=1\}\) (trials until first success). Then \(X\sim\mathrm{Geo}(\pi)\) on \(\{1,2,\ldots\}\) with \[ \mathbb P(X=x)=(1-\pi)^{x-1}\pi,\qquad F_X(x)=1-(1-\pi)^{\lfloor x\rfloor}. \] (Memoryless: \(\mathbb P(X=m+n\mid X>m)=(1-\pi)^{n-1}\pi=\mathbb P(X=n)\).)
\(X\sim \mathrm{Pois}(\lambda)\) on \(\{0,1,\dots\}\) has pmf \[ \mathbb P(X=x)=e^{-\lambda}\frac{\lambda^{x}}{x!}. \] \(\mathbb E[X]=\lambda,\ \mathrm{Var}(X)=\lambda,\ \varphi_X(s)=\exp\{\lambda(e^{s}-1)\}\). Reproductive: if \(X_i\sim \mathrm{Pois}(\lambda_i)\) independent then \(\sum_i X_i\sim \mathrm{Pois}(\sum_i\lambda_i)\). Extension (Poisson process): number of events in \([0,t]\) is \(N_t\sim \mathrm{Pois}(\lambda t)\).
If interarrival times of a Poisson process have rate \(\lambda>0\), then \(T\sim \mathrm{Exp}(\lambda)\) with cdf/pedf \[ F_T(t)=1-e^{-\lambda t}\ (t\ge0),\qquad f_T(t)=\lambda e^{-\lambda t}\ 1_{\{t\ge 0\}}. \]
For shape \(k>0\) and rate \(\lambda>0\), \[ X\sim \mathrm{Gamma}(k,\lambda)\quad\Longleftrightarrow\quad f_X(x)=\frac{\lambda e^{-\lambda x}(\lambda x)^{k-1}}{\Gamma(k)}\,1_{\{x>0\}}. \] If \(T_i\overset{\text{i.i.d.}}{\sim}\mathrm{Exp}(\lambda)\) then \(\sum_{i=1}^{n}T_i\sim \mathrm{Gamma}(n,\lambda)\).
Standard normal: \(Z\sim N(0,1)\) with \[ \varphi(z)=\frac{1}{\sqrt{2\pi}}e^{-z^2/2},\quad \Phi(z)=\int_{-\infty}^{z}\varphi(u)\,du. \] General normal: \(X\sim N(\mu,\sigma^2)\) has \[ f(x)=\frac{1}{\sqrt{2\pi}\,\sigma}\exp\!\left(-\frac{(x-\mu)^2}{2\sigma^2}\right). \] Standardisation: \(Z=(X-\mu)/\sigma\sim N(0,1)\).
If a population has \(N\) items with \(m\) successes and \(N-m\) failures, and we draw \(n\) without replacement, then \(X\sim\mathrm{Hyp}(n,m,N)\) with \[ \mathbb P(X=x)=\frac{\binom{m}{x}\binom{N-m}{n-x}}{\binom{N}{n}},\qquad x=0,1,\dots,n, \] and \(\ \mathbb E[X]=\frac{mn}{N}\).
For \(\alpha,\beta>0\), \(X\sim\mathrm{Beta}(\alpha,\beta)\) on \((0,1)\) with \[ f(x)=\frac{x^{\alpha-1}(1-x)^{\beta-1}}{B(\alpha,\beta)},\qquad B(\alpha,\beta)=\int_0^1 t^{\alpha-1}(1-t)^{\beta-1}\,dt. \]
Transformations of Random Variables
If \(Y=\phi(X)\) with \(\phi\) strictly monotone and differentiable, \[ f_Y(y)=f_X\!\big(\phi^{-1}(y)\big)\,\Big|\big(\phi^{-1}\big)’(y)\Big| = f_X\!\big(\phi^{-1}(y)\big)\,\left|\frac{1}{\phi’(\phi^{-1}(y))}\right|. \] (From \(F_Y\) by cases ↑/↓ and the inverse-function theorem.)
If \(Y=aX+b\) with \(a\neq0\) and \(X\) continuous, \[ f_Y(y)=\frac{1}{|a|}\,f_X\!\left(\frac{y-b}{a}\right). \]
If \(\phi\) is piecewise monotone with inverse branches \(\{\phi_k^{-1}:J_k\to I_k\}\), \[ f_Y(y)=\sum_k f_X\!\big(\phi_k^{-1}(y)\big)\, \Big|\big(\phi_k^{-1}\big)’(y)\Big|\;1_{\{y\in J_k\}}. \] (Useful e.g. \(Y=Z^2\) with \(Z\sim N(0,1)\Rightarrow Y\sim\chi^2_1\).)
If \(Y=\phi(X)\) where \(X=(X_1,X_2)\), \(Y=(Y_1,Y_2)\), \(\phi\) is one-to-one and differentiable with inverse \(\psi=\phi^{-1}\), then with Jacobian \(J(y)=\det\big[\partial \psi_i/\partial y_j\big]\), \[ f_Y(y)=f_X\!\big(\psi(y)\big)\,|J(y)|. \]
If \(X_1\perp\!\!\!\perp X_2\):
- Discrete: \(p_{X_1+X_2}(y)=\displaystyle\sum_{x} p_{X_1}(y-x)\,p_{X_2}(x)\).
- Continuous: \(f_{X_1+X_2}(y)=\displaystyle\int f_{X_1}(y-x)\,f_{X_2}(x)\,dx\).
If \(T_i\sim\mathrm{Exp}(\lambda_i)\) independent, \[ \min_i T_i\ \sim\ \mathrm{Exp}\!\Big(\sum_i\lambda_i\Big),\qquad \mathbb P\{\operatorname*{argmin}=j\}=\frac{\lambda_j}{\sum_i\lambda_i}. \]
If \(T_1,\dots,T_n\overset{\text{i.i.d.}}{\sim}\mathrm{Exp}(\lambda)\), then \(\sum_{i=1}^{n}T_i\sim\mathrm{Gamma}(n,\lambda)\).
If \(Z\sim N(0,1)\) and \(Y=e^{Z}\), then \[ f_Y(y)=\frac{1}{y\sqrt{2\pi}}\exp\!\left(-\frac{(\log y)^2}{2}\right),\quad y>0. \]
If \(Z\sim N(0,1)\) and \(Y=Z^2\), then \(Y\sim\chi^2_1\) with \[ f_Y(y)=\frac{1}{\sqrt{2\pi\,y}}\,e^{-y/2},\quad y>0. \] (Non-monotone transform handled by two branches \(Z=\pm\sqrt{y}\).)
If \(F_X\) is strictly increasing and \(U=F_X(X)\), then \(U\sim U(0,1)\).
Backlinks (4)
1. Multivariable Calculus /wiki/mathematics/calculus/mvars/
calculus in \(\mathbb{R}^n\): functions of several variables, the surfaces they define, and the fields that flow over them. the programme is the same as one variable — linearise locally, integrate globally — but the derivative becomes a matrix, the chain rule becomes matrix multiplication, and the fundamental theorem splits into three named theorems (green, stokes, gauss) that are secretly one (Courant, Richard, 1996). this page is also the mathematical spine of machine learning: gradients, hessians, jacobians and constrained optima are chapter 5 of (Deisenroth, Marc Peter and Faisal, A. Aldo and Ong, Cheng Soon, 2020).
2. Statistics /wiki/mathematics/statistics/
This page pairs well with Probability.
Table of Distributions
| Distribution | mass/density function | \[S_X\] | \[\mathbb{E}(X)\] | \[\mathrm{Var}(X)\] | \[\phi_X(s)\] |
|---|---|---|---|---|---|
| Bernoulli \[\mathrm{Bern}(\pi)\] | \[P(X=1)=\pi\\ P(X=0)=1-\pi\] | \[\{0,1\}\] | \[\pi\] | \[\pi(1-\pi)\] | \[(1-\pi)+\pi e^{s}\] |
| Binomial \[\mathrm{Bin}(n,\pi)\] | \[p_X(x)=\binom{n}{x}\pi^{x}(1-\pi)^{n-x}\] | \[\{0,1,\dots,n\}\] | \[n\pi\] | \[n\pi(1-\pi)\] | \[(1-\pi+\pi e^{s})^{n}\] |
| Geometric \[\mathrm{Geo}(\pi)\] | \[p_X(x)=\pi(1-\pi)^{x-1}\] | \[\{1,2,\dots\}\] | \[\pi^{-1}\] | \[(1-\pi)\pi^{-2}\] | \[\frac{\pi}{e^{-s}-1+\pi}\] |
| Poisson \[\mathcal{P}(\lambda)\] | \[p_X(x)=e^{-\lambda}\lambda^{x}/x!\] | \[\{0,1,\dots\}\] | \[\lambda\] | \[\lambda\] | \[\exp\{\lambda(e^{s}-1)\}\] |
| Uniform \[U[\alpha,\beta]\] | \[f_X(x)=(\beta-\alpha)^{-1}\] | \[[\alpha,\beta]\] | \[\frac{1}{2}(\alpha+\beta)\] | \[\frac{1}{12}(\beta-\alpha)^2\] | \[\frac{e^{\beta s}-e^{\alpha s}}{s(\beta-\alpha)}\] |
| Exponential \[\mathrm{Exp}(\lambda)\] | \[f_X(x)=\lambda e^{-\lambda x}\] | \[[0,\infty)\] | \[\lambda^{-1}\] | \[\lambda^{-2}\] | \[\frac{\lambda}{\lambda-s}\] |
| Gaussian \[\mathcal{N}(\mu,\sigma^{2})\] | \[f_X(x)=\frac{1}{\sqrt{2\pi\sigma^{2}}}\exp\left\{-\frac{(x-\mu)^2}{2\sigma^{2}}\right\}\] | \[\mathbb{R}\] | \[\mu\] | \[\sigma^{2}\] | \[e^{\mu s+\frac{1}{2}\sigma^{2}s^{2}}\] |
| Gamma \[\Gamma(\alpha,\lambda)\] | \[f_X(x)=\frac{1}{\Gamma(\alpha)}\lambda^{\alpha}x^{\alpha-1}e^{-\lambda x}\] | \[[0,\infty)\] | \[\alpha\lambda^{-1}\] | \[\alpha\lambda^{-2}\] | \[\left(\frac{\lambda}{\lambda-s}\right)^{\alpha}\] |
Statistical Inference
Let \(X=(X_1,\ldots,X_n)\) be i.i.d. from a parametric family \(\{F_\theta:\theta\in\Theta\subset\mathbb{R}^p\}\). The parameter \(\theta\) is unknown; inference uses the randomness of \(X\) to learn about \(\theta\).
3. Wiki /wiki/
Knowledge is a paradox. The more one understand, the more one realises the vastness of his ignorance.